The VBA Rnd function generates a random number that is greater than or equal to 0 and is less than 1.
The syntax of the function is:
Where [Number] is an optional numeric argument meaning:
Value of Number: | Random Number Generated: |
---|---|
< 0 | The same random number on each call, using [Number] as the seed. |
= 0 | The most recently generated random number |
> 0 (or omitted) |
The next random number in the sequence |
In the following example VBA code, each call to the Rnd function generates a different random number between 0 and 1:
' Generate three different random numbers between 0 and 1.
Dim rand1 As Double
Dim rand2 As Double Dim rand3 As Double
' Initialize the random number generator.
Randomize
rand1 = Rnd( )
' The variable rand1 is now equal to 0.705547511577606.
rand2 = Rnd( )
rand3 = Rnd( )' The variable rand2 is now equal to 0.533424019813538. ' The variable rand3 is now equal to 0.579518616199493. |
In the above VBA code, the [Number] argument has been omitted from the calls to the Rnd function. Therefore, each call to the function generates a different random number.
Note that, as recommended, the Randomize statement has been used to initialise the random number generator before the calls the Rnd function. Therefore, the above code will produce different random numbers each time it is run.
The following example VBA code illustrates how the different values for the [Number] argument affect the random numbers that are returned from the Rnd function.
' Generate random numbers between 0 and 1.
Dim rand1 As Double
Dim rand2 As Double Dim rand3 As Double Dim rand4 As Double
' Generate a random number relating to the seed value -2.
rand1 = Rnd( -2 ) ' The variable rand1 is now equal to 0.713325679302216.
' Generate the next random number in the sequence.
rand2 = Rnd( ) ' The variable rand2 is now equal to 0.662433266639709.
' Generate the random number relating to the seed value -2 (again).
' Produce the most recently generated random number.rand3 = Rnd( -2 ) ' The variable rand3 is now equal to 0.713325679302216. rand4 = Rnd( 0 ) ' The variable rand4 is now equal to 0.713325679302216. |
Note that, in the above VBA code:
If you want to produce a random Integer between two values lowerbound and upperbound, use the VBA Rnd and Int functions as follows:
A simple function that performs this is shown below:
' Generate a random integer between supplied lower and upper bounds.
Function RndInt( lowerbound As Integer,
upperbound As Integer )
As Integer
Randomize
End Function
RndInt = Int( lowerbound + Rnd( ) * ( upperbound - lowerbound + 1 ) ) |
In order to generate a random number between -5 and 5, for example, you could call the above function as follows:
' Generate a random integer between -5 and +5.
Dim rand1 As Integerrand1 = RndInt( -5, 5 ) |
Note that the Randomize statement has been used to initialise the random number generator in the above RndInt function. Therefore, this function will produce different random numbers each time the code is run.
If you want to produce a random decimal value between two values lowerbound and upperbound, use the following formula:
A simple function that performs this is shown below:
' Generate a random decimal between supplied lower and upper bounds.
Function RndDbl( lowerbound As Double,
upperbound As Double )
As Double
Randomize
End Function
RndDbl = lowerbound + Rnd( ) * ( upperbound - lowerbound ) |
In order to generate a random decimal that is greater than or equal to -5.0 and less than +5.0, for example, you could call the above function as follows:
' Generate a random decimal value between -5.0 and +5.0.
Dim rand1 As Doublerand1 = RndDbl( -5, 5 ) |
Again, note that the Randomize statement has been used to initialise the random number generator in the RndDbl function. Therefore, this function will produce different random numbers each time the code is run.
If the [Number] argument that is supplied to the Rnd function cannot be interpreted as a numeric value, the function will return the error: